1. Errata- In the first example there is
Also #(B>C) = 10 and
#(C>B) = 48, so C beats B by 44-10 = 34.
The 48 should be 44 apparently.
2. Regarding Mr. Anderson's --
A New Example:
48: A, (B & C tied)
6: B, (A & C tied)
46: C, B, A
I suggest again that the least worst defeat should not be used for a tie
breaker. There seems to be a bias using the least worst defeat tie breaker
towards the candidate with the second highest number of first choice votes.
For a tie breaker I suggest that the candidate with the lowest number of
first choice votes lose (or first choice votes plus additional choice votes
if there were 4 or more candidates). Thus B should lose the tie breaker and A
should win 48 to 46 (or 51 to 49 if a half vote for each of the 6 A & C tied
votes from B as second choices is transferred).